Let A and B be independent event with P (A ) = 0.3 and P (B) = 0.4. find
$P (\frac{B}{A})$

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Solution

We know that $P (\frac{B}{A}) = \frac{P (B \cap A)}{P (A)} = \frac{P (B) P (A)}{P (A)} \Rightarrow P (\frac{B}{A}) = \frac{0.12}{0.3} = 0.4$

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