CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
175
You visited us 175 times! Enjoying our articles? Unlock Full Access!
Question

Let 'a' and 'b' be positive integers. Show that root 2 lies between a/b and a+2b/a+b .

With full detailed solution of every step.

Open in App
Solution

Value of root(2) = 1.414

since a is an integer and b is also an positive integer so ..

a/b is a rational number ..!

If a >b then a/b > 1

also value of a/b can be greater than 1.414 in some cases ...Like (2/1) ( so a>b can not be the option ...a must be less than b)

So condition is if a < b ...then a/b is always less than 1 ...and hence 1.414 will always fall right side of the a/b value...on real axis ...means root 2 greater than a/b .

Now (a+2b)/(a+b) can be written as 1 +2 b/(a+b)

So it is always greater than one ... Critically when a=b ..it will be equal to 1.5 which is greater than 1.414

But once a > b .. the value can fall less than 1.414 ..example a= 2 and b=1 ...value will be 1.333

So Root(2) always lies between a/b and (a+2b)/(a+b) only if a < b ..

And i have shown above that ..how for a<b .. a/b is less than 1.414 and (a+2b)/(a+b) is greater than 1.414


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon