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Question

Let A and B be sets containing 2 and 4 elements respecetively. The number of subsets A×B having 3 or more elements is

A
219
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B
211
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C
256
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D
220
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Solution

The correct option is A 219
Let A={x,y}
B={a,bc,d}
A×B has 2×4=8 elements
Total substance of A×B=28=256
Total number of subsets of A×B having 3 or more elements
=256(1nullset+8singletonset8C2having2elements)
=256188!6!2!
=256188×7×6!6!2!
=2561828=219


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