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Question

Let A and B be the remainders when the polynomials y3+2y25ay7 and y3+ay212y+6 are divided by y+1 and y2 respectively. If 2A+B=6, find the value of a.

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Solution

y3+2y25ay7 leaves a remainder A, when divided by y+1.
So, plugging in y=1 in the above polynomial, we can find remainder A.
A=1+2+5a7=5a6

y3+2y25ay7 leaves a remainder B, when divided by y2.
So, plugging in y=2 in the above polynomial, we can find remainder A.
B=8+4a24+6=4a10

Given, 2A+B=6
10a12+4a10=6
14a22=6
14a=28
a=2

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