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Equality of 2 Complex Numbers

Let α and β b...

Question

Let α and β be the roots of x²-6x-2 =0 with α>β. If a_n = α_n - β_n for n≥1, then the value of

A

$1$

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B

$2$

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C

$3$

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D

$4$

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Solution

The correct option is B
$3$

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Similar questions

α

β

be the roots of equation

x^{2} - 6 x - 2 = 0

a_{n} = α^{n} - β^{n}

n \geq 1

, then the value of

\frac{a_{10} - 2 a_{8}}{2 a_{9}}

α

β

be the roots of equation

x^{2} - 6 x - 2 = 0

a_{n} = α^{n} - β^{n}

n ⩾ 1

, then the value of

\frac{a_{10} - 2 a_{8}}{2 a_{9}}

α

β

be the roots of equation

x^{2} - 6 x - 2 = 0

a_{n} = α^{n} - β^{n}

n \geq 1

, then the value of

\frac{a_{10} - 2 a_{8}}{2 a_{9}}

α

β

be the roots of

x^{2} - 6 x - 2 = 0

a_{n} = α^{n} - β^{n}

n \geq 1

, then the value of

\frac{a_{10} - 2 a_{8}}{3 a_{9}}

α

β

x^{2} - 6 (t^{2} - 2 t + 2) x - 2 = 0

α > β

a_{n} = α^{n} - β^{n}

\geq

, then find the minimum value of

\frac{a_{100} - 2 a_{98}}{a_{99}}

\in

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