Question

Let A and B be two fixed points in a plane. Find the locus of a point P such that $P{A}^2+P{B}^2=A{B}^2$

• A. Right triagle
• B. Circle with out A and B
• C. Semicircle with out A and B
• D. Square

Answer 1

Answer: (B)

Circle with out A and B

Given that A and B are two fixed points on a plane locus of P such that $P{A}^2+P{B}^2=A{B}^2$, such that $△$PAB is a right-angled triangle.

Let the points A and B be and points of a diameter of circle C.

The locus of point P are the points comprising circle C,less points A and B.

$\therefore$ The locus of a point is a circle without A and B