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Question

Let A and B be two fixed points in a plane. Find the locus of a point P such that PA2+PB2=AB2

A
Right triagle
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B
Circle with out A and B
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C
Semicircle with out A and B
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D
Square
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Solution

The correct option is C Circle with out A and B
Given that A and B are two fixed points on a plane locus of P such that PA2+PB2=AB2, such that PAB is a right-angled triangle.
Let the points A and B be and points of a diameter of circle C.
The locus of point P are the points comprising circle C,less points A and B.
The locus of a point is a circle without A and B

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