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Question

Let A and B be two non empty sets such that n(A)=5, n(B)=6 and n(AB)=3.

Find (i) n(A×B),

(ii) n(B×A) and

(iii) n(A×B)(B×A)

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Solution

(i) n(A×B)=n(A)×n(B)=(5×6)=30

(ii) n(B×A)=n(B)×n(A)=(6×5)=30

(iii) Given: n(AB)=3

A and B have 3 elements in common.

So, (A×B) and (B×A) have 32=9 elements in common.

Hence, n(A×B)(B×A)=9


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