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Question

Let A and B be two non-null square matrices. If the product AB is a null matrix, then

A
A is singular
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B
B is singular
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C
A is non-singular
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D
B is non-singular
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Solution

The correct options are
B A is singular
D B is singular
Let B be non-singular, then B1 exists.
Now, AB=0( given)(AB)B1=0B1
( post multiplying both sides by B1)
A(BB1)=0 ( by associativity )
AIn=0(BB1=In)
A=0
But A is a non-null matrix.
Hence B is a singular matrix.
Similarly, it can be shown that A is a singular matrix.

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