Let A and B be two sets containing 2 elements and 4 elements respectively. The number of subsets of A×B having 3 or more elements is
A
256
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B
220
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C
219
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D
211
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Solution
The correct option is C 219 A=x,yB=a,b,c,dA×Bhaving2×4=8elementsTotalsubsetsA×B=28=256∴Totalno.ofsubsetsofA×Bhaving3ormoreelements=256−⎛⎜⎝188C2null+singleton+subsethavingsetset2elemints⎞⎟⎠=256−1−8−28=219