Let A and B be two sets. Show that the sets A×B and B×A have an element in common if the sets A and B have an element in common.
Let (a, b) be an arbitary element of (A×B)∩(B×A). Then,
(a,b)ϵ(B×A). Then,
(a,b)ϵ(A×B)∩(B×A)
⇔(a,b)ϵA×B and (a,b)ϵB×A
⇔(a,ϵ A and b ϵ B)and (a ϵ B and b ϵ A)
⇔(a,ϵ A and a ϵ B)and (b ϵ A and b ϵ B)
⇔a ϵ A ∩ B and b ϵ A ∩ B
Hence, the sets A×B and B×A have an element in common iff the sets A and have an element in common.