Question

Let A and B be two sets such that $A\times B$ consists of 6 elements. If three elements of $A\times B$ are (1,4), (2,6), (3, 6), find $A\times B$ and $B\times A$.

Answer 1

From the given ordered pair of $A\times B$ we conclude that
A= {1, 2, 3}, B={4, 6}
Since $A\times B$ has six elements i.e. $3\times 2$ and hence A and B are as stated above.
$\therefore A\times B$ ={(1,4), (1, 6), (2, 4), (2, 6), (3,4), (3, 6)}
By reserving the above ordered pairs, we get
$B\times A$ = { (4, 1), (6, 1), (4, 2), (6, 2), (4, 3), (6, 3)}.