Let A and B be two sets such that nA-16- nB-12- and nA- B-8- Then nA- B equals

The correct option is B 20 n(A∪ B)=n(A)+n(B) n(A∩ B)=16+12 8=20 ...

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Let $A$ and $B$ be two sets such that $n (A) = 16$ , $n (B) = 12$ , and $n (A \cap B) = 8$ . Then $n (A \cup B)$ equals

28

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20

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36

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12

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Let A and B be two sets such that n (A) = 20, n (A \cup B) = 42 and n (A \cap B) = 5 . Then, n (B - A) =

Let A and B be two sets such that n (A) = 16, n(B) = 14, $n (A \cup B)$ = 25. Then, $n (A \cap B)$ is equal to .

A

B

n (A) = 20

n (B) = 28

n (A \cup B) = 36

n (A \cap B)

A

B

n (A) = 70

n (B) = 90

n (A \cup B) = 110

n (A \cap B)

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