Let A and B be two sets such that n (A) = 16, n(B) = 14, n(A∪B)= 25. Then, n(A∩B) is equal to .
30
50
5
none of these
We know :
n(A∪B)=n(A)+n(B)−n(A∩B)
Now,
n(A∩B)=n(A)+n(B)−n(A∪B)
= 16+14-25
= 5