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Question

Let A and B be two sets such that n(A)=3 and n(B)=2. If (x,1),(y,2),(z,1) are in A×B, then find A and B, where x,y,z are distinct elements.

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Solution

Given:
n(A)=3 and n(B)=2; and (x,1),(y,2),(z,1) are in A×B.

Apply cartesian product of two sets
As we know,
A= Set of first elements of the ordered pair elements of A×B
B= set of second elements of the ordered pair elements of A×B
So, it is clear that set A= {x,y,z} and set B= {1,2}.

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