Let A and B denote the statements A:cosα+cosβ+cosγ=0 B : sinα+sinβ+sinγ=0 If cos(β−γ)+cos(γ−α)+cos(α−β)=−3/2, then
A
A is true and B is false
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B
A is false and B is true
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C
both A and B are true
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D
both A and B are false
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Solution
The correct option is A both A and B are true cos(β−γ)+cos(γ−α)+cos(α−β)=−3/2 ⇒2cos(β−γ)+2cos(γ−α)+2cos(α−β)=−3 ⇒2Σcosβcosγ+2Σsinαsinβ+3=0 ⇒(cosα+cosβ+cosγ)2+(sinα+sinβ+sinγ)2=0 ⇒cosα+cosβ+cosγ=0 and sinα+sinα+sinγ=0 Hence, option 'C' is correct.