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Question

Let A and B denote the statements
A:cosα+cosβ+cosγ=0
B : sinα+sinβ+sinγ=0
If cos(βγ)+cos(γα)+cos(αβ)=3/2, then

A
A is true and B is false
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B
A is false and B is true
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C
both A and B are true
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D
both A and B are false
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Solution

The correct option is A both A and B are true
cos(βγ)+cos(γα)+cos(αβ)=3/2
2cos(βγ)+2cos(γα)+2cos(αβ)=3
2Σcosβcosγ+2Σsinαsinβ+3=0
(cosα+cosβ+cosγ)2+(sinα+sinβ+sinγ)2=0
cosα+cosβ+cosγ=0 and sinα+sinα+sinγ=0
Hence, option 'C' is correct.

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