Let A,B and C are distinct positive integers, less than or equal to 10. If the arithmetic mean of A and B is 9 and the geometric mean of A and C is 6√2, then the harmonic mean of B and C is
A
8619
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
16017
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
18019
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
8617
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C18019 Given, A+B=18…(1) AC=72…(2) There are only two possibilities i.e. A=10 and B=8 or A=8 and B=10. If A=10, then from equation (2),C is non integer. Hence, A=8,B=10 and C=9