Question

Let $a,b$ and $c$ be non-zero numbers such that $c$ is $24$ greater than $b$ and $b$ is $24$ greater than $a$. If $\frac{c}{a}=3$, then find the value of $b$.

• A. $-48$
• B. $-24$
• C. $24$
• D. $48$

Answer 1

The correct option is D $48$

Let the value of $a$ be $x$

Thus, $b$ would be $24+x$

and $c$ is $24+24+x=48+x$.

Given, $\frac{c}{a}=3$

Therefore, $\frac{48+x}{x}=3$

$\Rightarrow 2x=48$

$\Rightarrow x=24$

Value of $b$ is $24+x=24+24=48$.