Let A,B and C be pairwise independent events with P(C)>0 and P(A∩B∩C)=0 Then, P(AC∩BC/C) is equal to
A
P(AC)−P(B)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
P(A)−P(BC)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
P(AC)+P(BC)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
P(AC)−P(BC)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is AP(AC)−P(B) P(AC∩BCC)=P((AC∩BC)∩C)P(C)=P((1−A)(1−B)⋅C)P(C)=P[(1−A−B+AB)⋅C]P(C)=P(C)−P(CA)−P(CB)+P(ABC)P(C)=P(C)−P(C)⋅P(A)−P(C)⋅P(B)+P(A)P(B)P(C)P(C)=P(C)−P(C)⋅P(A)−P(C)⋅P(B)+P(A∩B∩C)P(C)=1−P(A)−P(B)=P(AC)−P(B)Hence,optionAiscorrectanswer.