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Question

Let A,B and C be pairwise independent events with P(C)>0 and P(ABC)=0 Then, P(ACBC/C) is equal to

A
P(AC)P(B)
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B
P(A)P(BC)
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C
P(AC)+P(BC)
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D
P(AC)P(BC)
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Solution

The correct option is A P(AC)P(B)
P(ACBCC)=P((ACBC)C)P(C)=P((1A)(1B)C)P(C)=P[(1AB+AB)C]P(C)=P(C)P(CA)P(CB)+P(ABC)P(C)=P(C)P(C)P(A)P(C)P(B)+P(A)P(B)P(C)P(C)=P(C)P(C)P(A)P(C)P(B)+P(ABC)P(C)=1P(A)P(B)=P(AC)P(B)Hence,optionAiscorrectanswer.

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