Let a, b and c be positive constants. The value of ‘a’ in terms of ‘c’ if the value of integral ∫10(acxb+1+a3bx3b+5) dx is independent of ‘b’ equals
A
√3c2
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B
√2c3
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C
√c3
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D
√32c
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Solution
The correct option is A√3c2 If the integral is independent of b, then I’(b) = 0 ⇒I′(b)=−ac(b+2)2+D(a33.(b+2−2b+2))=−ac(b+2)2+2(b+2)2 =1(b+2)2(2a33−ac)⇒2a33=ac⇒a=√3c2