Question

Let $a,b$ and $c$ be real numbers such that $4a+2b+c=0$ and $ab>0$. Then the equation $a{x}^2+bx+c=0$ has

• A. complex roots
• B. exactly one root
• C. real roots
• D. none of these

Answer 1

Answer: (C)

real roots

Given quadratic equation is $a{x}^2+bx+c=0$

Now putting $x=2$ in the above equation, we get

$4a+2b+c=0$

which means that one real root of the equation is 2

Now since one real root of the equation is 2, other root must be real.

Hence the roots of the equation are real and distinct.