The correct option is D If (A−C)⊆B, then A⊆B
Let A={1,2,3} B={2,3,4} C={1,2,3,5,6}
Here, A∩B={2,3}⊆C
we can clearly see that
A−C=ϕ⊆B
But A⊈B So, option (d) is false
(A−B)={1}⊆C, and ∵A∩B={2,3}⊆C , therefore A⊆C
(C∪A)∩(C∪B)={1,2,3,5,6}∩{1,2,3,4,5,6}=C
B∩C={2,3}≠ϕ