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Question

Let a,b and c be three non-zero vectors, no two of which are collinear. If the vector a+2b is collinear with c, and b+3c is collinear with a, then a+2b+6c is equal to
(λ being some non-zero scalar) then a+2b+6c=

A
λ a
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B
λ b
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C
λ c
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D
0
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Solution

The correct option is B 0
Let a+2b=xc and b+3c=ya.
Then a+2b+6c=(x+6)c
and also, a+2b+6c=(1+2y)a,
So (x+6)c=(1+2y)a.
Since a,b and c are non-zero and non-collinear,
we have x+6=0
and 1+2y=0, i.e. x=6 and y=1/2,
In either case, we have a+2b+6c=0

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