Let a,b and c be three non-zero vectors, no two of which are collinear. If the vector a+2b is collinear with c, and b+3c is collinear with a, then a+2b+6c is equal to (λ being some non-zero scalar) then a+2b+6c=
A
λa
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B
λb
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C
λc
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D
0
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Solution
The correct option is B0 Let a+2b=xc and b+3c=ya. Then a+2b+6c=(x+6)c and also, a+2b+6c=(1+2y)a, So (x+6)c=(1+2y)a. Since a,b and c are non-zero and non-collinear, we have x+6=0 and 1+2y=0, i.e. x=−6 and y=−1/2, In either case, we have a+2b+6c=0