Question

Let A,B are two sets such that n(A)=4 and n(B)=6. Then the least possible number of elements in the power set of $(A\cup B)$ is

• A. 16
• B. 64
• C. 256
• D. 1024

Answer 1

The correct option is D 1024

Given,

$n\left(A\right)=4,n\left(B\right)=6$

Then the least number of possible elements in

$n(A\cup B)=2^{n\left(A\right)}{.2}^{n\left(B\right)}=2^4{.2}^6=2^{10}=1024$