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Question

Let α & β be the roots of \({x^2}\) – 6x – 2= 0 which α >β . if an= αnβn for n1 , then the

value of a102a82a9 is


A

4

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B

3

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C

1

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D

2

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Solution

The correct option is B

3


α2 - 6α - 2=0------------(1)
β2 -6β -2 =0 ------------(2)
α102α82α9 = (α10β10)2(α8β8)2(α9β9) = α8(α22)β8(β22)2(α9β9)
= α36αβ86β2(α9β9) =3


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