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Question

Let A, B be two matrices such that they commute, then for any positive integer n,
(i) ABn=BnA (ii) (AB)n=AnBn

A
only (i) is correct
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B
both (i) and (ii) are correct
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C
only (ii) is correct
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D
none of (i) and (ii) is correct
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Solution

The correct option is A both (i) and (ii) are correct
Given, AB=BA
Now, for (i)
Taking AB2=(AB)B
=(BA)B
=B(AB)
=B(BA)=B2A
(AB2)=B2A
AB3=(AB2)B=(B2A)B
=B2(AB)=B2BA
=B3A
AB3=B3A
Hence, ABn=BnA
Now, for (ii)
Taking (AB)2=(AB)(AB)
=A(BA)B
=A(AB)B=A2B2
(AB)2=A2B2
Now, (AB)3=(AB)(AB)(AB)
=A(BA)(BA)B
=A(AB)(AB)B
=A2(BA)B2
=A2(AB)B2
=A3B3
Hence, for (AB)n=AnBn

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