Let A, B be two matrices such that they commute, then for any positive integer n, (i) ABn=BnA (ii) (AB)n=AnBn
A
only (i) is correct
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B
both (i) and (ii) are correct
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C
only (ii) is correct
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D
none of (i) and (ii) is correct
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Solution
The correct option is A both (i) and (ii) are correct Given, AB=BA Now, for (i) Taking AB2=(AB)B =(BA)B =B(AB) =B(BA)=B2A ⇒(AB2)=B2A AB3=(AB2)B=(B2A)B =B2(AB)=B2BA =B3A ⇒AB3=B3A Hence, ABn=BnA Now, for (ii) Taking (AB)2=(AB)(AB) =A(BA)B =A(AB)B=A2B2 ⇒(AB)2=A2B2 Now, (AB)3=(AB)(AB)(AB) =A(BA)(BA)B =A(AB)(AB)B =A2(BA)B2 =A2(AB)B2 =A3B3 Hence, for (AB)n=AnBn