Let a, b be two positive numbers, where a>b and 4×GM=5×HM for the numbers. Then a is
A
4b
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B
14b
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C
2b
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D
b
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Solution
The correct option is A 4b Given 4√ab=5×2aba+b ⇒(a+b)=5√ab2_________(1) ⇒a2+b2+2ab=25ab4 ⇒(a+b)=52√ab ⇒a2+b2−2ab=9ab4 ⇒a−b=3√ab2(∵a>b)______(2) ∴2a=4√ab from (1) and (2) ⇒a=4b