Let a, b, c and d be non-zero numbers. If the point of intersection of the lines 4ax+2ay+c=0 and 5bx+2by+d=0 lies in the fourth quadrant and is equidistant from the two axes then
A
2bc−3ad=0
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B
2bc+3ad=0
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C
3bc−2ad=0
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D
3bc+2ad=0
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Solution
The correct option is B3bc−2ad=0
Solve the equations of two lines to get a point and satisfy it in the third equation of a line.