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Question

Let a, b, c be distinct non-negative numbers. If the vectors ai+aj+ck+,i+k and ci+cj+bk lie in a plane, then c is

A
the AM of a and b
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B
the GM of a and b
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C
the HM of a and b
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D
equal to zero
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Solution

The correct option is D the GM of a and b
ai+aj+ck+,i+k and ci+cj+bk are coplanar.
∣ ∣aac101ccb∣ ∣=0
acab+ac+c2=0
c2=ab
i.e c is GM of a and b
Hence, option B.

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