CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Let A,B,C be finite sets. Suppose that n(A)=10,n(B)=15,n(C)=20,n(AB)=8 and n(BC)=9. Then the maximum possible value of n(ABC) is 


Solution

n(ABC)=n(A)+n(B)+n(C)n(AB)                           n(BC)n(CA)+n(ABC)                        =28[n(CA)n(ABC)]
We know that n(CA)n(ABC)n(CA)n(ABC)0
Maximum possible value of n(ABC) is 28

Mathematics

Suggest Corrections
thumbs-up
 
1


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image