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Question

Let a,b,c be positive and not all equal. Show that the value of the determinant ∣ ∣abcbcacab∣ ∣ is negative.

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Solution

Expanding along R1
=a(bca2)b(b2ac)+c(abc2)
=3abc(a3+b3+c3)
=[a3+b3+c33abc]
=[(a+b+c)(a2+b2+c2abbcca)]
=12[(a+b+c)(2a2+2b2+2c22ab2bc2ca)]
=12[(a+b+c)((ab)2+(bc)2+(ca)2)]
=ve (therefore, a,b,c are positive and distinct)

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