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Question

Let a,b,c be positive real numbers. The following system of equations in x,y and z
x2a2+y2b2z2c2=1, x2a2y2b2+z2c2=1, x2a2+y2b2+z2c2=1 has

A
no solution
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B
unique solution
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C
infinitely many solutions
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D
finitely many solutions
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Solution

The correct option is B unique solution
Δ=∣ ∣ ∣ ∣ ∣ ∣1a21b21c21a21b21c21a21b21c2∣ ∣ ∣ ∣ ∣ ∣=1a2b2c2∣ ∣111111111∣ ∣

=1a2b2c2∣ ∣200111111∣ ∣=4a2b2c20
Given system has unique solution.
Hence, option B.

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