Let a-b-c be real - if a x 2 -bx-c-0 has two real roots - and - where -1- then show that c a - b a - -y Find y

For a x ^ 2 +bx+c=0 nbsp; α lt; 1 and nbsp;β gt;1 Therefore, f( 1)f(1) lt;0 Therefore, ⇒( c+b+a ) ( c b+a ) lt;0 ⇒ c ...

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Theorems for Differentiability

Let a,b,c be ...

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Let a,b,c be real , if $a x^{2} + b x + c = 0$ has two real roots $α$ and $β$ , where $α < - 1 a n d β > 1$ , then show that $\frac{c}{a} + ∣ ∣ ∣ \frac{b}{a} ∣ ∣ ∣ < - y$ Find y

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∣ ∣ ∣ ∣ \begin{matrix} 2 & α & δ β & 0 & α γ & β & 1 \end{matrix} ∣ ∣ ∣ ∣

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