Let a- b- c be such that 1-1-x1-2x1-3x-a-1-x-b-1-2x-c-1-3x then a-1-b-3-c-5-

The correct option is A 1/15 Substitute x=2 1( 1)( 3)( 5)=a 1+b 3+c 5 Therefore, a1+b3+c5=115 ...

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Summation by Sigma Method

Let a, b, c...

Question

Let $a, b, c$ be such that $\frac{1}{(1 - x) (1 - 2 x) (1 - 3 x)} = \frac{a}{1 - x} + \frac{b}{1 - 2 x} + \frac{c}{1 - 3 x}$ then $\frac{a}{1} + \frac{b}{3} + \frac{c}{5} =$

\frac{1}{15}

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\frac{1}{6}

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\frac{1}{5}

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\frac{1}{3}

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Solution

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Similar questions

\frac{(1 + x) (1 + 2 x) (1 + 3 x)}{(1 - x) (1 - 2 x) (1 - 3 x)} = K +

\frac{A}{1 - x} + \frac{B}{1 - 2 x} + \frac{C}{1 - 3 x}

\frac{1}{(1 - 2 x) (1 + 3 x)}

= \frac{A}{1 - 2 x} + \frac{B}{1 + 3 x}

2 B =

f (x) = \frac{x}{1 + x} + \frac{x}{(1 + x) (1 + 2 x)} + \frac{x}{(1 + 2 x) (1 + 3 x)} + . . . . \infty

a, b, c \in R^{+}

a + \frac{1}{b} = 3, b + \frac{1}{c} = 4, c + \frac{1}{a} = \frac{9}{11}

a b c =

5 (3 - x) - 2 (4 - 3 x) = 11 - 2 (x - 1)

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