Let a, b, c be the vectors of lengths 3, 4, 5 respectively. If each one is perpendicular to the sum of other two, then find the magnitude of vector a+b+c.
A
3√3
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B
4√2
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C
5√2
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D
6√2
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Solution
The correct option is C5√2 Given, a.(b+c)=0,b.(c+a)=0,c.(a+b)=0 Adding these, 2(a.b+b.c+c.a)=0 Also a2=∣∣a2∣∣=9,b2=16,c2=25 Now (a+b+c)2=Σa2+2Σa.b=9+16+25+0+=50 ∴|a+b+c|=5√2