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Question

Let a,b,c be three distinct positive real numbers. If p,q,r lie in a plane, where p=aiaj+bk, q=i+k and r=ci+cj+bk, then b is

A
AM of a,c
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B
GM of a,c
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C
HM of a,c
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D
Equal to 0
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Solution

The correct option is D HM of a,c
The condition for coplanarity of vectors p,q,r gives
∣ ∣aab101ccb∣ ∣=0

ac+a(bc)+b(c)=ab2ac+bc=0

Dividing throughout by abc, we have
1c+1a=2b

a,b,c are in H.P.

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