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Question

let a,b,c be three distinct real numbers such that each of the expression ax2+bx+c,bx2+cx+aand cx2+ax+b is positive for each x belongs to R and let alpha = (bc+ca+ab)/(a2+b2+c2);
(A) alpha <4 (B) alpha <1 (C) alpha >1/4 (D) alpha >1

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Solution

ax2+bx+c>0 xRa>0 and b2-4ac<0 ...1 bx2+cx+a>0 xRb>0 and c2-4ab<0 ...2cx2+ax+b>0 xRc>0 and a2-4bc<0 ...3Adding (1), (2) and (3), we geta2+b2+c2-4ab-4bc-4ca<0a2+b2+c2<4ab+4bc+4caab+bc+caa2+b2+c2>14α>14

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