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Question

Let a, b, c be three non-zero real numbers such that the equation 3acosx+2bsinx=c, xϵ[π2,π2] has two distinct real roots α and β with α+β=π3. Then the value of 2ba is ___________.

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Solution

3cosx+2basinx=ca

3cosα+2basinα=ca .......(1)

3cosβ+2basinβ=ca ........(2)
Consider (1)(2)
3[cosαcosβ]+2ba(sinαsinβ)=0

3[2sin(α+β2)sin(αβ2)]+2ba[2cos(α+β2)sin(αβ2)]=0

3+23ba=0

ba=12=0.5.

2ba=1

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