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Question

Let a,b,c be three vectors. Then show that
¯¯¯a×(¯¯bׯ¯c)=(¯¯¯a.¯¯c)¯¯b(¯¯¯a.¯¯b)¯¯c

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Solution


Let r=(a×b)×c
since, cross product of two vectors is a vector perpendicular to both the vectors
r=a×(b×c) -----(1)
raandr(b×c)
But (b×c) is a vector perpendicular to the plane of b and c therefore
r(b×c)
r lies in the plane b and c
$ \Rightarrow \overrightarrow r $ is expressible as linear combination of b and c
Thereexistscalerx,y
such that
r=xb+yc(2)
Now
ra
r.a=0
(xb+yc).a=0

x(b.a)+y(c.a)=0

x(a.b)+y(a.c)=0

x(a.b)=y(a.c)

x(a.c)=y(a.b)=λ(say)

x=λ(a.c)
y=λ(a.b)
Substituting the vector of x and y in (2) we get
r=λ(a.c)bλ(a.b)c

r=λ[(a.c)bλ(a.b)c]

a×(b×c)=λ[(a.c)bλ(a.b)c]
This is vector identity and so it is true a,b,c
a×(b×c)=(a.c)b(a.b)c
Hence, the given question is proved

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