Let A- B- C can be pairwise independent events with PC - 0 and P A - B - C-0-Then PAc - Bc - Cc is equal to-

The correct option is A P(A^c) P(B) [ P[ A^ C ∩ B^ C / C #160; ] = P( A^ C ∩ B^ C ∩ C ) #160; / P( C ) #160; ...

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Definition of Sets

Let A, B, C c...

Question

Let A, B, C can be pairwise independent events with $P (C) > 0$ and $P (A \cap B \cap C) = 0$ .
Then $P (A^{c} \cap B^{c} | C^{c})$ is equal to:

P (A^{c}) - P (B)

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P (A) - P (B^{c})

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P (A^{c}) + P (B^{c})

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P (A^{c}) - P (B^{c})

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Solution

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Similar questions

A, B

C

P (C) > 0

P (A \cap B \cap C) = 0

P (A^{C} \cap B^{C} / C)

A, B, C

P (A \cap B^{C} \cap C^{C}) = \frac{1}{4}, P (A^{C} \cap B \cap C^{C}) = \frac{1}{8}, P (A^{C} \cap B^{C} \cap C^{C}) = \frac{1}{4}

P (A), P (B), P (C)

A

B

P (A \cup B) = \frac{1}{2}, P (A \cap B) = \frac{2}{5}

P (A^{c}) + P (B^{c})

[IIT 1983]

A

B

P (A \cup B) = 0.65

P (A \cap B) = 0.15

P (A^{c}) + P (B^{c})

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