Let a, b, c, d and e be integers such that a = 6b = 12c, and 2b = 9d = 12e. Then which of the following pairs contains a number that is not an integer ?

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Solution

The correct option is D | |
Assumption

Start with e. if e=12, then c=36, d=16, b=72 and a=432

Now you can eliminate answer options. All the options, other than option (d) give integral values.

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Similar questions

Let a, b, c, d and e be distinct integers such that (6 - a) (6 - b) (6 - c) (6 - d) (6 -e) = 45. What is a+b+c+d+e?

Let a, b, c, d and e be distinct integers such that (6 - a) (6 - b) (6 - c) (6 - d) (6 - e) = 45. What is a+b+c+d+e?

a + b < c + d

b + c < d + e

c + d < e + a

d + e < a + b

a, b, c, d, e

a + b = b + c = c + d = d + e = 2015

a + b + c + d + e = 5030

(d - a)

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