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Question

Let a,b,c,dR+ and 256abcd(a+b+c+d)4 and 3a+b+2c+5d=11 then a3+b+c2+5d is

A
15
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B
8
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C
11
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D
20
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Solution

The correct option is B 8
Given: 256abcd(a+b+c+d)4(abcd)14(a+b+c+d)4
We know that A.MG.M
(a+b+c+d)4(abcd)14
So both expression satisfies only when A.M=G.M
a=b=c=d
We know that
3a+b+2c+5d=11a=1=b=c=d
Hence the value of the expression
a3+b+c2+5d=8

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