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Quantitative Aptitude

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Let A, B, C, ...

Question

Let A, B, C,... X,Y,Z be positive numbers such that AC=B,BD=C...XZ=Y.Given that A+B=1988 find max value of Y+Z?

994

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1988

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√1988

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3976

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none of these

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Solution

The correct option is B 1988
Solution:

Let A = x and C =y

Then B = xy

$D = \frac{1}{x}$

$E = \frac{1}{x y}$

$F = \frac{1}{y}$

G = x

H = xy

I = y

So we see that this is a sequence with a period six. So A = Y and B = Z

Given A+B = 1988, so max value of Y+Z = 1988.

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Let A, B, C,... X,Y,Z be positive numbers such that AC=B,BD=C...XZ=Y.Given that A+B=1988 find max value of Y+Z?

The correct option is B 1988Solution: Let A = x and C =y Then B = xy D=1x E=1xy F=1y G = x H = xy I = y So we see that this is a sequence with a period six. So A = Y and B = Z Given A+B = 1988, so max value of Y+Z = 1988.

The correct option is B 1988
Solution:

Let A = x and C =y

Then B = xy

$D = \frac{1}{x}$

$E = \frac{1}{x y}$

$F = \frac{1}{y}$

G = x

H = xy

I = y

So we see that this is a sequence with a period six. So A = Y and B = Z

Given A+B = 1988, so max value of Y+Z = 1988.