Let a*b denote the length of the hypotenuse of a right angle triangle whose remaining two sides have length a, b. If (12*16)*k=25 then find the value of k2.
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Solution
If length of base and altitude of a right triangle is a and b, then length of hypotenuse is given that a*b but by pythogorus theorem we know that length of hypotenuse is root(a^2+b^2) so by comparing this a*b=root(a^2+b^2) so 12*16=root(12^2+16^2) =root(144+256) =20 20*k=25(given ) so root(20^2+k^2)=25 root(400+k^2)=25 squre both sides then 400+k^2=625 k^2=625-400=225