Question

Let A BCDEF be a regular hexagon with each side of length 1cm. The area (in sq cm) of a square with AC as one side is

• A. $3\sqrt{2}$
• B. 3
• C. 4
• D. $\sqrt{3}$

Answer 1

The correct option is B

3

Consider the diagram given below:



AM is the height of the triangle AOB, also AC = 2AM
AM = $\frac{\sqrt{3}}{2}\times \left(1\right)=\frac{\sqrt{3}}{2}$
AC = 2 $\times \frac{\sqrt{3}}{2}$ = √3
Area of the square = $Sid{e}^2$ = $(\surd 3{)}^2$ = 3 sq. cm