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Question

Let A be a 3×3 matrix such that P=1α3133244, P=adj(A) and |A|=4, then the value of α is

A
11
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B
12
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C
15
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D
20
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Solution

The correct option is A 11
Given, P=adj(A)
|P|=|adj(A)|
|P|=|A|31=|A|2
∣ ∣1α3133244∣ ∣=16

1(1212)α(46)+3(46)=162α6=16α=11

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