Let A be a square matrix of order n×n. A constant λ is said to be characteristic root of A if there exists a n×1 matrix X such that AX=λX
Let P be a non-singular matrix, then which of the following matrices have the same characteristic roots.
A
A and AP
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B
A and PA
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C
A and P−1AP
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D
none of these
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Solution
The correct option is DA and P−1AP Since X≠0 is such that (A−λI)X=0,|A−λI|=0⇔A−λI is singular. If A−λI is non-singular the then equation (A−λI)X=0⇒X=0 If λ=0, we get |A|=0⇒A is singular. We have A2X=A(AX)=A(λX)=λ(AX) =λ2X, A3X=A(A2X)=A(λ2X) =λ2(AX)=λ2(λX)=λ3X Continuing in this way, we obtain A"X=λ′′X∀n∈N Also,|P−1AP−λI|=|P−1(A−λI)P| =|P−1||A−λI||P|=|A−λI|