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Question

Let A be a square matrix of order n×n. A constant λ is said to be characteristic root of A if there exists a n×1 matrix X such that AX=λX

If λ is a characteristic root of A and nN, then λn is a characteristic root of

A
An
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B
An1
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C
An
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D
AAn+An
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Solution

The correct option is B An
Since X0 is such that (AλI)X=0,|AλI|=0AλI is singular. If AλI is non-singular the then equation (AλI)X=0X=0
If λ=0, we get |A|=0A is singular.
We have A2X=A(AX)=A(λX)=λ(AX)
=λ2X,
A3X=A(A2X)=A(λ2X)
=λ2(AX)=λ2(λX)=λ3X
Continuing in this way, we obtain
AnX=λnXnN

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