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Byju's Answer
Standard XII
Mathematics
Inverse of a Matrix
Let A be any ...
Question
Let A be any
3
×
3
invertible matrix. Then which one of the following is not always true?
A
a
d
j
(
a
d
j
(
A
)
)
=
|
A
|
⋅
(
a
d
j
(
A
)
)
−
1
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B
a
d
j
(
a
d
j
(
A
)
)
=
|
A
|
2
⋅
(
a
d
j
(
A
)
)
−
1
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C
a
d
j
(
a
d
j
(
A
)
)
=
|
A
|
⋅
A
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D
a
d
j
(
A
)
=
|
A
|
⋅
A
−
1
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Solution
The correct option is
A
a
d
j
(
a
d
j
(
A
)
)
=
|
A
|
⋅
(
a
d
j
(
A
)
)
−
1
we know that
A
.
a
d
j
A
=
|
A
|
I
2
a
d
j
(
a
d
j
(
A
)
)
=
|
A
|
n
−
2
A
=
|
A
|
3
−
2
A
=
|
A
|
.
A
so 3rd is correct
using
a
d
j
A
=
|
A
|
A
−
1
.....4th is true
a
d
j
(
a
d
j
A
)
=
|
a
d
j
A
|
(
a
d
j
A
)
−
1
=
|
A
|
2
(
a
d
j
A
)
−
1
so 2nd is true
we can say 1 st is wrong option
Suggest Corrections
0
Similar questions
Q.
Let
A
be a
2
×
2
matrix
Statement 1:
a
d
j
(
a
d
j
A
)
=
A
Statement 2:
|
a
d
j
A
|
=
(
|
A
|
(
n
−
1
)
)
Q.
If A is a square matrix such that
A
(
A
d
j
A
)
=
⎡
⎢
⎣
4
0
0
0
4
0
0
0
4
⎤
⎥
⎦
, then
|
A
d
j
(
A
d
j
A
)
|
A
d
j
A
|
is equal to
Q.
Let
A
be a
3
×
3
square matrix. If
B
=
a
d
j
(
A
)
,
C
=
a
d
j
(
a
d
j
(
A
)
)
and
D
=
a
d
j
(
a
d
j
(
a
d
j
(
A
)
)
)
,
then
|
a
d
j
(
a
d
j
(
a
d
j
(
a
d
j
(
A
B
C
D
)
)
)
)
|
,
in terms of
|
A
|
is
Q.
lf A is a
3
x
3
non singular matrix and
|
a
d
j
A
|
=
|
A
|
x
,
|
a
d
j
(
a
d
j
A
)
|
=
|
A
|
y
,
|
A
−
1
|
=
|
A
|
z
then the values of
x
,
y
,
z
, in descending order
Q.
Let
A
be a
3
×
3
square matrix and matrices
B
,
C
and
D
are related such that
B
=
a
d
j
(
A
)
,
C
=
a
d
j
(
a
d
j
A
)
and
D
=
(
a
d
j
(
a
d
j
(
a
d
j
A
)
)
)
.
If
det
(
a
d
j
(
a
d
j
(
a
d
j
(
a
d
j
A
B
C
D
)
)
)
)
)
=
|
A
|
k
,
then the value of
k
is
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