Let a be any element in a boolean algebra B. If a+x = 1 and ax =0, then
Let A = {x : |x-1|< 3} and B = {x : x2 – 2ax + a2 – 4 ≥ 0} be two sets. If A∩B={x:−2<x≤1}, then the smallest positive integral value of ‘a’ is ___